1. LPU MCA Semester 1
  2. PEA515
  3. Unit 4

PEA515 · Unit 4: Ratio, proportion and mixtures

Alligation rule

30 practice questions · in the ETE syllabus

Key points

  • Cheaper : dearer = (dearer - mean) : (mean - cheaper)
  • Subtract crosswise from the mean
  • Convert selling price to cost price before alligation
  • Pure ingredient quantity is unchanged when water is added

Alligation finds the ratio in which two ingredients of different prices (or strengths) are mixed to get a mixture of a given mean value. If the cheaper costs c, the dearer costs d and the mean is m, then

cheaper : dearer = (d - m) : (m - c).

Write the mean in the middle, the two prices on either side, and subtract crosswise: each ingredient's quantity is proportional to the distance of the other price from the mean. The same rule works for concentrations of solutions, for example mixing 25% and 35% solutions to get 29% needs them in the ratio (35 - 29) : (29 - 25) = 3 : 2.

ProblemIdea
Ratio from pricesAlligation on cost prices
Mean price from a ratioWeighted average
Selling price for a gain g%Cost price x (100 + g) / 100
Selling price given, ratio askedConvert to the cost price first, then use alligation
Water added to a mixtureThe quantity of the pure ingredient does not change

Example: rice at 26 and 32 rupees per kg must give a mixture worth 27 rupees per kg, so cheaper : dearer = (32 - 27) : (27 - 26) = 5 : 1.

Exam trap: apply alligation to the cost price. If a selling price and a profit percentage are given, convert to cost first.

Try two questions

Question 1 · Tier 3, Apply

A 36 litre solution has 75% milk. Water is added until the milk is 50% of the total. How many litres of water are added?

  1. 9
  2. 18
  3. 54
  4. 19
Show the answer

B. Milk is 27 litres. For 50% milk the total must be 54 litres, so 18 litres of water are added.

Why not A: Takes the percentage drop of the original quantity.

Why not C: Gives the new total quantity instead of the water added.

Why not D: Arithmetic slip in the final step.

Question 2 · Tier 2, Understand

A chemist mixes a 19% salt solution with 32 litres of a 64% salt solution to obtain a 39% solution. How many litres of the 19% solution are used?

  1. 25.6
  2. 32
  3. 72
  4. 40
Show the answer

D. By alligation x : 32 = (64 - 39) : (39 - 19) = 5 : 4, so x = 40.

Why not A: Inverts the ratio of the two quantities.

Why not B: Assumes equal quantities of both solutions.

Why not C: Gives the total quantity of the mixture.