- LPU MCA Semester 1
- PEA515
- Unit 5
PEA515 · Unit 5: Permutation, combination and probability
Conditional probability
30 practice questions · in the ETE syllabus
Key points
- P(A given B) = P(A and B) / P(B)
- The condition reduces the sample space
- Without replacement, the second draw has fewer cards
- Independent events multiply
Conditional probability P(A | B) is the probability of A given that B has happened. The condition shrinks the sample space to B, so
P(A | B) = P(A and B) / P(B).
| Situation | Result |
|---|---|
| First die shows 4, sum at least 6 | Only 6 outcomes remain; the second die must be 2 or more, so 5/6 |
| Two cards without replacement, first is a king | 51 cards remain and 3 are kings, so 3/51 = 1/17 |
| Group data: 62 drink tea, 48 drink both | P(coffee given tea) = 48/62 = 24/31 |
| Independent events | P(A and B) = P(A) x P(B), and P(A given B) = P(A) |
| Bayes-type question | Compare the defective items of one source with all defective items |
For independent events A and B with P(A) = 1/3 and P(B) = 1/2: P(A or B) = 1/3 + 1/2 - 1/6 = 2/3, and P(neither) = (2/3)(1/2) = 1/3.
In a Bayes-type problem, if machine A makes 40% of items with 2% defective and B makes 60% with 3% defective, then P(A given defective) = (40 x 2) / (40 x 2 + 60 x 3) = 80 / 260 = 4/13.
Exam trap: divide by the size of the condition, not by the whole sample space.
Try two questions
Two fair dice are thrown. Given that the first die shows 2, what is the probability that the sum is at least 7?
- 1/18
- 7/12
- 1/3
- 1/6
Show the answer
C. With the first die fixed at 2, the second die must be at least 5: 2 of 6 outcomes.
Why not A: Divides by all 36 outcomes instead of the 6 that remain.
Why not B: Ignores the information about the first die.
Why not D: Treats the outcome as a single face.
In a group of 60 people, 25 drink tea, 35 drink coffee and 8 drink both. If a person who drinks tea is chosen at random, what is the probability that the person also drinks coffee?
- 8/35
- 8/25
- 2/15
- 7/12
Show the answer
B. Of the 25 tea drinkers, 8 also drink coffee: 8/25.
Why not A: Divides by the wrong group.
Why not C: Gives the probability of both without the condition.
Why not D: Gives the unconditional probability.